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The number of terms in the expansion of (1 x)^101 (1 x^2-x)^100 in powers of x is:
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The number of terms in the expansion of (1+x)^101 (1+x^2-x)^100 in powers of x is:
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Number of terms in (1+x)^101(1+x^2-x)^100 is (A) 302 (B) 301 (C) 202 P
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IIT JEE BINOMIAL THEOREM Find the number of terms in the expansion of `(1+x)^(101)xx(1+x^2-x)^(10...
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In the expansion of `(1+x)^n` the coefficients of terms equidistant from the beginning and th
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The number of terms whose values depend on x in the expansion of (x^2-2+1/x^2)^n is (a) 2 n+1 (b)...
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Binomial Expansion of 1/1-x and 1/1+x
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The number of terms in the expansion of `(1+5sqrt2 x)^9+(1-5sqrt2 x)^9` is
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T h e n u m b e r o f t e r m s `(x+a)^(100)+(x-a)^100` The number of terms in the expansion af...
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Total no. of distinct terms in the expansion (x1+x2+............+xr)^n #shorts
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The number of terms in the expansion of `(1+2x+x^2)^(20)` when expanded in decreasing powers o
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Human Calculator Solves World’s Longest Math Problem #shorts
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The total number of dissimilar terms in the expansion of (x + a)^(100) + (x-a)^(100) after simp...
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If the middle term in the expansion of (x² + 1/x)' is 924 x⁶, then find the value of n.
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If coefficient of xn in (1 + x)101 (1 – x + x2)100 is non zero,
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The number of distinct terms in the expansion of \( \left(x+\frac{1...
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JEE MAINS 2018 The number of terms in the expansion of `(x^2+1+1/x^2)^n, n in N` , is:
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Genius trick to solve this impossibly hard question
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Logarithmic Form to Exponential Form 🤯 #Shorts #algebra #math #maths #mathematics #education #learn
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Binomial Theorem | How to find Total Number of Terms for Binomial Expansion | TGT PGT Maths Dsssb
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Write the total number of terms in the expansion (x+a)100+(x-a)100|Binomial Theorem|RD Sharma|11|CET
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23 - The Binomial Theorem & Binomial Expansion - Part 1
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The total number of terms in the expansion of \( (x+a)^{100}+(x-a)^...
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Binomial theorem SE13: Coefficient of x^2 in (1+x)^2+(1+x)^3+..+(1+x)^49+(1+mx)^50 is (3n+1)51C3.
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Short Trick to Find number of terms in trinomial | For KVS/ NDA/ TGT/ PGT Mathematics #Shorts
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